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Answer: Option 4

$$\eqalign{ & {\text{Milk in 1st glass}} \cr & = \frac{1}{2}{\text{ unit}} \cr & {\text{Milk in 2nd glass}} \cr & = \frac{3}{4}{\text{ unit}} \cr & {\text{Water in 1st glass}} \cr & = \frac{1}{2}{\text{ unit}} \cr & {\text{Water in 2nd glass}} \cr & = \frac{1}{4}{\text{ unit}}{\text{}} \cr & \therefore {\text{Required ratio}} \cr & = \frac{{\frac{1}{2} + \frac{3}{4}}}{{\frac{1}{2} + \frac{1}{4}}} \cr & = \frac{5}{4} \times \frac{4}{3} \cr & = 5:3 \cr} $$

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