- 120
- 360
- 720
- 840
- None of these
Answer: Option 2
Keeping the vowels (AIA) together, we have CPTL (AIA). We treat (AIA) as 1 letter. Thus, we have to arrange 5 letters. These can be arranged in 5! = (5 × 4 × 3 × 2 × 1) ways = 120 ways Now, (AIA) are 3 letters with 2A and 1I These can be arranged among themselves in $$\frac{{3!}}{{2!}} = \frac{{3 \times 2 \times 1}}{{2 \times 1}} = 3$$ ways ∴ Required number of ways = 120 × 3 = 360