When the belt is transmitting maximum power, the belt speed should be (Where, m = mass of belt per meter (kg/m) and Pmax = maximum permissible tension in belt (N))?

$$\sqrt {\frac{{{\text{P}}\max }}{{2{\text{m}}}}} $$
$$\sqrt {\frac{{{\text{P}}\max }}{{3{\text{m}}}}} $$
$$\sqrt {\frac{{{\text{P}}\max }}{{\text{m}}}} $$
$$\sqrt {\frac{{{\text{3m}}}}{{{\text{P}}\max }}} $$

LohaHridoy

9 views

2025-01-04 04:42

1 Answers

AhmedNazir

Answer: Option 2

Let'

9 views Answered 2022-09-01 13:21

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