What is the number of degree of freedom for a system of two miscible non-reacting species in vapor-liquid equilibrium forming an azeotrope?

LohaHridoy
  1. 3
  2. 2
  3. 1
  4. 0

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Answer: Option 3

The given number of component $$= 2$$ Given number of phases $$= 2$$ We know, $${\text{degree of freedom (number of independent variables) }} = C - \phi + 2$$ $$\left( {{\text{assuming no reaction taking place}}} \right)$$ $$f = 2 - 2 + 2 = 2$$ And since under azeotropic conditions the composition of a component in both the phases remains same one of the independent variable becomes dependent and hence the degree of freedom reduces to 1.

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