- $$\frac{{4}}{{9}}$$
- $$\frac{{5}}{{9}}$$
- $$\frac{{7}}{{9}}$$
- $$\frac{{8}}{{9}}$$
Answer: Option 2
Two balls can be picked from nine balls in $${{}^9{C_2}}$$ ways. We select one white ball and one red ball from five white balls and four red balls. This can be done $${{}^5{C_1}}$$ . $${{}^4{C_1}}$$ ways. ∴ The required probability $$\eqalign{ & = \frac{{5 \times 4}}{{{}^9{C_2}}} \cr & = \frac{{20}}{{36}} \cr & = \frac{5}{9} \cr} $$