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উপায়-১: 3!+5+11+13+15=50 এখানে, 3!=1*2*3 উপায়-২: 1+3+7+13+15 =3+13+7+15+1 =III+XIII+VII+XV+I =II(I+XI+V)+XV+I =2(1+11+5)+15+1 =2 (17)+16 =34+16 =50
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