3 Answers

PQ=(1+sinA)(1-sinA) =(1^2)-sinA+sinA-(sin^2 A) =(1^2)-(sin^2 A) =1-sin^2 A (ans)

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P=1+SinA Q=1-SinA PQ=(1)^2-(Sin)^2 =1-Sin^2A =Cos^2A

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সমাধান দেওয়া হল-

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