Simple Harmonic Motion MCQ

Test your knowledge with important Simple Harmonic Motion MCQ and their applications. These MCQs are beneficial for competitive exams too. Explore 30 + more Simple Harmonic Motion MCQs at Bissoy

• The frequency of oscillation of a torsional pendulum is
  ক

  2πkG/r √g/I

  খ

  r/2πkG√g/I

  গ

  2πkG/r√I/g

  ঘ

  r/2πkG√I/g
• The centre of percussion is below the centre of gravity of the body and is at a distance equal to
  ক

  h / kG

  খ

  h.kG

  গ

  h2/kG

  ঘ

  k2G/h
• The equivalent length of a simple pendulum which gives the same frequency as the compound pendulum is
  ক

  h/ k2G +h2

  খ

  k2G +h2/h

  গ

  h2/k2G +h2

  ঘ

  k2G +h2/h2
• The frequency of oscillation of a compound pendulum is
  ক

  1/2π √g.h/k2G +h2

  খ

  1/2π √k2G +h2/g.h

  গ

  2π√g.h/k2G +h2

  ঘ

  2π√k2G +h2/g.h
• When a rigid body is suspended vertically and it oscillates with a small amplitude under the action of the force of gravity, the body is known as
  ক

  simple pendulum

  খ

  torsional pendulum

  গ

  compound pendulum

  ঘ

  second’s pendulum
• The frequency of oscillation for the simple pendulum is
  ক

  1/2π √L/g

  খ

  1/2π √g/L

  গ

  2π √L/g

  ঘ

  2π√g/L
• The maximum acceleration of a particle moving with simple harmonic motion is
  ক

  ω

  খ

  ω.r

  গ

  ω2.r

  ঘ

  ω2/r
• The velocity of a particle (v) moving with simple harmonic motion, at any instant is given by
  ক

  ω √r2 − x2

  খ

  ω √x2 − r2

  গ

  ω2 √r2 − x2

  ঘ

  ω2√x2 − r2
• The velocity of a particle moving with simple harmonic motion is . . . . at the mean position.
  ক

  zero

  খ

  minimum

  গ

  maximum

  ঘ

  none of the mentioned
• The periodic time (tp) is given by
  ক

  ω / 2 π

  খ

  2 π / ω

  গ

  2 π × ω

  ঘ

  π/ω
• In SHM, what is the phase difference between velocity and acceleration?
  ক

  0

  খ

  π

  গ

  π/2

  ঘ

  π/3
• In an SHM the time taken to go from mean position to A/2 is the same as that from A/2 to A. True or False? Here, A is the amplitude of motion.
  ক

  True

  খ

  False
• What is the amplitude of motion for x = 2sin(2t) + 4sin2t ?
  ক

  2√2 m

  খ

  4 m

  গ

  2 m

  ঘ

  The given equation is not that of an SHM
• A particle starts from the extreme position, at t = 0, in a SHM. If the time period of motion is 2s & maximum speed is 5m/s, find the equation of motion.
  ক

  x = 1.59cos(πt)

  খ

  x = 1.59sin(πt)

  গ

  x = 2.5sin(2t)

  ঘ

  x = 2.5cos(2t)
• A particle has an equation of motion given by: x = cos2wt – sin2wt. Select the correct statement regarding the same.
  ক

  It is not a SHM

  খ

  It is a SHM with T = π/w

  গ

  It is an SHM with T = 2π/w

  ঘ

  Amplitude of motion is 1/√2 m
• 2 particles undergoing SHM start from the mean position and go in opposite directions. Particle 1 starts with a speed of 10m/s and particle 2 starts with a speed 0f 5m/s. If the amplitude(=10cm) is the same. At what position will they first meet?
  ক

  0.0866m

  খ

  -0.0633m

  গ

  0

  ঘ

  0.0633m
• A particle is undergoing SHM with amplitude 10cm. The maximum speed it achieves is 1m/s. Find the time it takes to reach from the mean position to half the amplitude.
  ক

  π/60 s

  খ

  π/30 s

  গ

  π/15 s

  ঘ

  π/40 s
• Which of the following variables has zero value at the extreme position in SHM?
  ক

  Acceleration

  খ

  Speed

  গ

  Displacement

  ঘ

  Angular frequency