The rate of the following redox reaction is slowest when X is [CoIII(NH3)5X]3+/2+ + [CrII(H2O)6]2+ → [CoII(NH3)5(H2O)]2+ + [CrIII(H2O)5X]3+/2+

The rate of the following redox reaction is slowest when X is [CoIII(NH3)5X]3+/2+ + [CrII(H2O)6]2+ → [CoII(NH3)5(H2O)]2+ + [CrIII(H2O)5X]3+/2+ Correct Answer NH<sub>3</sub>

Explanation:-

  • Henry Taube, a Nobel prize-winning scientist, In 1983 discovered the process of determination of solvation numbers and lability.
  • He explained the process of inner-sphere electron transfer of Ruthenium and Osmium ammine complexes in a combination of unsaturated ligands and mixed-valence complexes.
  • It is possible for any of the three steps to be limiting rate depending on the particular ligand set and metal dn.
  • Taube’s experiment has rate limiting electron transfer due to Cr(II). 
  • Both the starting Co3+ (d6) and product Cr3+ (d3 ) chloride complexes are inert so Cl- transfer must have occurred via a bridge species.

3+/2+ + 2+ → 2+ + 3+/2 

= Low spin non- liable Co(III) + High spin liable Cr(II)→ High spin liable Co(II) + Low spin non-liable Cr(III)

Here, X = NH3

 2+ + 2+ + 5 H2O →  2+ + 2+ + 5 NH3

2+ + 2+→ 4+ + H2O 

4+→  4+

4+ + H2O → 4+ +  4+

2+ + 5 H2O → 2+ + 5 NH3

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