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What is the output of following program? abstract class Sum { public abstract int sumOfTwo(int n1, int n2); public abstract int sumOfThree(int n1, int n2, int n3); public void disp( ){ System.out.println("Method of class Sum"); } } class DemoAbstract1 extends Sum { public int sumOfTwo(int num1, int num2) { return num1+num2; } public int sumOfThree(int num1, int num2, int num3) { return num1+num2+num3; } public static void main(String args[ ]){ Sum obj = new DemoAbstract1( ); System.out.println(obj.sumOfTwo(3, 7)); System.out.println(obj.sumOfThree(4, 3, 19)); obj.disp( ); } }
What will happens if the statement free(a) is removed in the following C code?
#include#includemain(){ int *a; a=(int*)malloc(sizeof(int)); *a=100; printf("*a%d",*a); free(a); a=(int*)malloc(sizeof(int)); *a=200; printf("a%p",a); *a=200; printf("a%d",*a);}
Comment on the following 2 C programs.
#include  //Program 1int main(){ int a; int b; int c;}#include  //Program 2int main(){ int a; { int b; } { int c; }}
What is the output of this program ? #include
using namespace std;
int n(char, int);
int (*p) (char, int) = n;
int main()
{
(*p)('d', 9);
p(10, 9);
return 0;
}
int n(char c, int i)
{
cout << c << i;
return 0;
}
Comment on the output of the following C code.
#include int main(){ int a = 1; switch (a) case 1: printf("%d", a); case 2: printf("%d", a); case 3: printf("%d", a); default: printf("%d", a);}
The following C code is an example of . . . . . . . .
#include#include#includemain(){ char *p,*q; p=(char*)malloc(3*sizeof(char)); q=p; strcpy(p,"hello"); printf("p=%s",p); printf("q=%s",q); free(q); q=NULL; gets(p); gets(q); printf("%s",p); printf(“%s”,q);}
What will output when you compile and run the following code?#include
struct student
{ int roll;
int cgpa;
int sgpa[8]; }; void main()
{ struct student s = { 12,8,7,2,5,9 };
int *ptr;
ptr = (int *)&s;
clrscr();
printf( "%d", *(ptr+3) );
getch(); }
Which of the following is an external variable in the following C code?
#include int func (int a){ int b; return b;}int main(){ int c; func (c);}int d;
What will be the final values of i and j in the following C code?
#include int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) | g(); //bitwise or int j = g() | (f() + g()); //bitwise or}
What will be the final values of i and j in the following C code?
#include int x = 0;int f(){ if (x == 0) return x + 1; else return x - 1;}int g(){ return x++;}int main(){ int i = (f() + g()) || g(); int j = g() || (f() + g());}