∫Indx=?
A
1/x
B
∞
C
x(In x-1)
D
x(In x+1)
Correct Answer: x(In x-1)
দেয়া আছে, ∫In x dx = ∫In x ×1dx = Inx ∫ 1× dx - ∫ddxInx ∫1×dx ×dx = In × x - ∫1x × xdx = x In - ∫ 1 × dx = x Inx - x + c = x (Inx - 1) + c