if(2x2+3x-5)(x+2)=ax3+bx2+3x+d, then ac-bd=?

if(2x2+3x-5)(x+2)=ax3+bx2+3x+d, then ac-bd=? Correct Answer 72

দেয়া আছে, (2x2 + 3x - 5)(x + 2) = ax3 + bx2 + cx + d⇒ 2x3 + 3x2 - 5x + 4x2 + 6x - 10 = ax3 + bx2 + cx + d⇒ 2x3 + 7x2 + x - 10 = ax3 + bx2 + cx + d উভই পক্ষকে তুলনা করে পাই, a = 2 b = 7 c = 1 d = - 10 .:. ac - bd = (2 × 1) - 7( - 10) = 2 + 70 = 72
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