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Which one of these is the right preposition of Adjacent?

Which one of these is the right preposition of Adjacent? Correct Answer to

’সংলগ্ন বা নিকটবর্তী’ অর্থে Adjacent এর পরে preposition হিসেবে to বসে।

Related Questions

7 sports personalities representing different sports are sitting around a round table facing inside. The person representing Cricket is sitting in between of those who represent Basketball and Badminton. The one who represents Tennis is sitting in adjacent left of Chess representative. Hockey representative is sitting in adjacent left of the person who represents Basketball. The one represents Tennis is in adjacent right of Football representative. Which sports does the person represents who is in adjacent left of Football representative?
If a + b + c + d = 4, then find the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?
If a + b + c + d = 4, then the value of $$\frac{1}{{\left( {1 - a} \right)\left( {1 - b} \right)\left( {1 - c} \right)}}$$     + $$\frac{1}{{\left( {1 - b} \right)\left( {1 - c} \right)\left( {1 - d} \right)}}$$     + $$\frac{1}{{\left( {1 - c} \right)\left( {1 - d} \right)\left( {1 - a} \right)}}$$     + $$\frac{1}{{\left( {1 - d} \right)\left( {1 - a} \right)\left( {1 - b} \right)}}$$     is?
8 friends – P, Q, R, S, T, U, V and W are sitting in a row facing north. S is 2ndd to the right of T who is sitting at the extreme left end. U is sitting adjacent to S but to its left side. V is sitting 3rd to the right of U. Adjacent to V is W. 2nd to the right of W is R. P is sitting adjacent to S. Who is sitting at the 5th position from the left end? 
Each of the six different faces of a cube has been coated with a different colour i.e., V, I, B, G, Y and O. Following information is given: i. Colours Y, O and B are on adjacent faces. ii. Colours I, G and Y are on adjacent faces. iii. Colours B, G and Y are on adjacent faces. iv. Colours O, V and B are on adjacent faces. Which is the colour of the face opposite to the face coloured with O?
Five boys are sitting in a row. Rohan is not adjacent to Sameer or Aman. Anubha is not adjacent to Sameer. Rohan is adjacent to Mohit. Mohit is at middle in the row. Then Anubha is adjacent to whom out of the following?
Eight friends – A, B, C, D, E, F, G and H participated in a play where all the students are sitting around a circular table, facing centre and were tagged with different numbers from 1 to 8. C was tagged with number 5 and was sitting third to the right of the person with tag 3. G was sitting opposite to person with tag 5 and adjacent to person with tag 7. B got the tag 3. Person with tag 4 is sitting 3rd to the right person with tag 7. H has tag 7 and is sitting 3rd to the left of A. Opposite to A is D with tag 1. E is sitting adjacent to C but not adjacent to A. F got the tag 2. Person sitting between C and D has tag 6. Who is sitting opposite to H?
Seven friends, H, I, J, K, L, M, and N are sitting in a row facing South. M is third to the right of H who is to the immediate right of K. H is sitting third to the right of I who is at one of the extreme ends. K is sitting adjacent to L and M is not sitting adjacent to N. Who is sitting second to the right of H?
The value of the expression $$\frac{{{{\left( {a - b} \right)}^2}}}{{\left( {b - c} \right)\left( {c - a} \right)}} + $$   $$\frac{{{{\left( {b - c} \right)}^2}}}{{\left( {a - b} \right)\left( {c - a} \right)}} + $$    $$\frac{{{{\left( {c - a} \right)}^2}}}{{\left( {a - b} \right)\left( {b - c} \right)}}$$   = ?
The Hamiltonian of a particle is given by $$H = \frac{{{p^2}}}{{2m}} + V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right) + \phi \left( { + \left| {\overrightarrow {\bf{r}} } \right|} \right)\overrightarrow {\bf{L}} .\overrightarrow {\bf{S}} ,$$        where $$\overrightarrow {\bf{S}} $$ is the spin, $$V\left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$  and $$\phi \left( {\left| {\overrightarrow {\bf{r}} } \right|} \right)$$  are potential functions and $$\overrightarrow {\bf{L}} \left( { = \overrightarrow {\bf{r}} \times \overrightarrow {\bf{p}} } \right)$$   is the angular momentum. The Hamiltonian does not commute with