Related Questions

For crushing of solids, the Rittinger's law states that the work required for crushing is proportional to
A The new surface created
B The size reduction ratio
C The change in volume due to crushing
D None of these
What is the usual value of angle of nip for crushing of ordinary rock in smooth steel crushing rolls?
A 16°
B 32°
C 40°
D 46°
Choke crushing (in case of a Jaw crusher) compared to free crushing
A Results in increased capacity
B Consumes less power
C Consumes more power
D Both A and C
Crushing resistance required to crush the rivet per pitch length is
A $${\text{pd}}{\sigma _{\text{c}}}$$
B $${\text{pt}}{\sigma _{\text{c}}}$$
C $${\text{ndt}}{\sigma _{\text{c}}}$$
D $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}}{\sigma _{\text{c}}}$$
The pull required to tear off the plate per pitch length is (where p = Pitch of rivets, t = Thickness of plates and $${\sigma _{\text{t}}},\,\tau $$  and $${\sigma _{\text{c}}}$$ = Permissible tensile, shearing and crushing stresses respectively)
A $$\left( {{\text{p}} - 2{\text{d}}} \right){\text{t}} \times {\sigma _{\text{c}}}$$
B $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times \tau $$
C $$\left( {{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$
D $$\left( {2{\text{p}} - {\text{d}}} \right){\text{t}} \times {\sigma _{\text{t}}}$$
Energy consumed for crushing one ton of material ranges from __________ kWh.
A 0.01 to 0.1
B 0.5 to 1.5
C 2 to 3.5
D 4 to 5
When you are given a set of tables and asked to create a database to store their data, the first step is to create the new database.
A True
B False
Which of the following is used for primary crushing of very hard lumpy materials?
A Toothed roll crusher
B Gyratory crusher
C Ball mill
D Tube mill
Which of the following crushing laws is most accurately applicable to the fine grinding of materials ?
A Bond's crushing law
B Kick's law
C Rittinger's law
D None of these
The work index in Bond's law for crushing of solids has the following dimensions
A No units (dimensionless)
B kWh/ton
C kW/ton
D $${\text{kWh}}.{{\text{m}}^{\frac{1}{2}}}/{\text{ton}}$$

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