The sphericity of a solid particle of cubical shape is
A
$$\pi $$
B
$${\left( {\frac{\pi }{6}} \right)^{\frac{1}{3}}}$$
C
$${\left( {\frac{\pi }{6}} \right)^{\frac{1}{2}}}$$
D
$$\frac{\pi }{3}$$
Correct Answer: $${\left( {\frac{\pi }{6}} \right)^{\frac{1}{3}}}$$