In an irreversible process
A
Tds = dE - dW = 0
B
DE - dW - Tds = 0
C
Tds - dE + dW
D
Tds - dT + dW
Correct Answer: Tds - dE + dW
From second law of thermodynamics :$$\eqalign{ & TdS \geqslant \delta Q \cr & \Rightarrow TdS \geqslant dU + \delta W \cr} $$
For an irreversible process $$TdS - dU - \delta W > 0$$
And for an reversible process $$TdS - dU - \delta W = 0$$
