The root mean square speed of molecules of a gas is equal to (where, m = mass of the molecule K = Boltzman's constant, T = absolute temperature)

A $$\sqrt {\frac{{2{\text{KT}}}}{{\text{m}}}} $$
B $$\sqrt {\frac{{3{\text{KT}}}}{{\text{m}}}} $$
C $$\sqrt {\frac{{6{\text{KT}}}}{{\text{m}}}} $$
D $$\frac{{3{\text{KT}}}}{{\text{m}}}$$

Correct Answer: $$\sqrt {\frac{{3{\text{KT}}}}{{\text{m}}}} $$

empirical relation:
Root mean square speed $$ = \sqrt {\frac{{3KT}}{m}} $$

Whereas average velocity $$ = \sqrt {\frac{{8KT}}{{\pi m}}} $$
Bissoy MCQ
#Chemical Engineering #Chemical Engineering Thermodynamics

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