The root mean square speed of molecules of a gas is equal to (where, m = mass of the molecule K = Boltzman's constant, T = absolute temperature)
The root mean square speed of molecules of a gas is equal to (where, m = mass of the molecule K = Boltzman's constant, T = absolute temperature) Correct Answer $$\sqrt {\frac{{3{\text{KT}}}}{{\text{m}}}} $$
empirical relation:Root mean square speed $$ = \sqrt {\frac{{3KT}}{m}} $$
Whereas average velocity $$ = \sqrt {\frac{{8KT}}{{\pi m}}} $$