Related Questions

The angle between the observer's meridian and declination circle of a heavenly body, is known as
A Hour angle
B Azimuth
C Right ascension
D Declination
The latitude of a place was obtained by subtracting the zenith distance of a star from its declination, the observed star was between
A Horizon and equator
B Equator and zenith
C Zenith and pole
D Pole and horizon
The latitude of a place was obtained by subtracting the declination of a star from its zenith distance, the observed star was between
A Horizon and equator
B Zenith and pole
C Equator and zenith
D Pole and horizon
When a star is between the pole and the horizon, the relationship between latitude (λ), zenith distance (z) and declination δ, is
A θ = z + δ
B θ = δ - z
C θ = 180° - (z + δ)
D θ = (z + δ) - 180°
If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer then the hour angle of the star at elongation is given by
A sin H = tan φ . cot δ
B cos H = tan φ . cot δ
C tan H = tan φ . cot δ
D None of these
If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer, then the azimuth of the star at elongation is given by
A sin z = sec φ . cos δ
B cos z = sec φ . cos δ
C tan z = sec φ . cos δ
D None of these
The altitude of a heavenly body is its angular distance, measured on the vertical circle passing through the body, above
A Equator
B Horizon
C Pole
D None of these
A star may culminate at zenith if its declination is
A Greater than the longitude of the place
B Less than the latitude of the place
C Equal to the latitude of the place
D None of these
At upper culmination, the pole star moves
A Eastward
B Westward
C Northward
D Southward
Right ascension of a heavenly body is its equatorial angular distance measured
A Westward from the first point of Libra
B Eastward from the first point of Aeries
C Westward from the first point of Aeries
D Eastward from the first point of Libra

Next steps