If the kinetic energy and potential energy of a simple harmonic oscillator of amplitude A are both equal to half the total energy, then the displacement is equal to
A
$${\text{A}}$$
B
$$\frac{{\text{A}}}{2}$$
C
$$\frac{{\text{A}}}{{\sqrt 2 }}$$
D
$${\text{A}}\sqrt 2 $$
Correct Answer: $$\frac{{\text{A}}}{{\sqrt 2 }}$$