The centre of gravity of an isosceles triangle with base (p) and sides (q) from its base is
A
$$\frac{{\sqrt {4{{\text{p}}^2} - {{\text{q}}^2}} }}{6}$$
B
$$\frac{{4{{\text{p}}^2} - {{\text{q}}^2}}}{6}$$
C
$$\frac{{{{\text{p}}^2} - {{\text{q}}^2}}}{4}$$
D
$$\frac{{{{\text{p}}^2} + {{\text{q}}^2}}}{4}$$
Correct Answer: $$\frac{{\sqrt {4{{\text{p}}^2} - {{\text{q}}^2}} }}{6}$$
