The height of a Watt's governor (in meters) is equal to (where N = Speed of the arm and ball about the spindle axis)
A
$$\frac{{8.95}}{{{{\text{N}}^2}}}$$
B
$$\frac{{89.5}}{{{{\text{N}}^2}}}$$
C
$$\frac{{895}}{{{{\text{N}}^2}}}$$
D
$$\frac{{8950}}{{{{\text{N}}^2}}}$$
Correct Answer: $$\frac{{895}}{{{{\text{N}}^2}}}$$
