The effort of a Porter governor is equal to (where c = Percentage increase in speed, m = Mass of ball and M = Mass on the sleeve)

A $${\text{c}}\left( {{\text{m}} - {\text{M}}} \right){\text{g}}$$
B $${\text{c}}\left( {{\text{m}} + {\text{M}}} \right){\text{g}}$$
C $$\frac{{\text{c}}}{{\left( {{\text{m}} + {\text{M}}} \right){\text{g}}}}$$
D $$\frac{{\text{c}}}{{\left( {{\text{m}} - {\text{M}}} \right){\text{g}}}}$$

Correct Answer: $${\text{c}}\left( {{\text{m}} + {\text{M}}} \right){\text{g}}$$

Bissoy MCQ
#Mechanical Engineering #Theory of Machine

Related Questions

The ratio of height of Porter governor (when length of arms and links are equal) to the height of Watt's governor is (where m = Mass of the ball and M = Mass on the sleeve)
A $$\frac{{\text{m}}}{{{\text{m}} + {\text{M}}}}$$
B $$\frac{{\text{M}}}{{{\text{m}} + {\text{M}}}}$$
C $$\frac{{{\text{m}} + {\text{M}}}}{{\text{m}}}$$
D $$\frac{{{\text{m}} + {\text{M}}}}{{\text{M}}}$$
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