Related Questions

Sum of 4 consecutive even numbers is greater than three consecutive odd numbers by 81 . If the sum of the least odd and even numbers is 59 then find the sum of largest of odd and even numbers is 59 then find the sum of largest odd and even numbers.
There are 4 consecutive odd numbers (x1, x2, x3 and x4) and three consecutive even numbers (y1, y2 and y3). The average of the odd numbers is 6 less than the average of the even numbers. If the sum of the three even numbers is 16 less than the sum of the four odd numbers, what is the average of x1, x2, x3 and x4?
The sum of three consecutive odd numbers and three consecutive even numbers together is 231. Also, the smallest odd number is 11 less than the smallest even number. What is the sum of the largest odd number and the largest even number ?
Sum of 4 consecutive even numbers is greater than consecutive odd numbers by 81. If the sum of the least odd and even numbers is 59 then find the sum of largest odd and even numbers.
Consider the given question and decide which of the following statements is sufficient to answer the question. All natural numbers are whole numbers?
(I) All natural numbers plus 0 are called whole numbers (II) Whole numbers are different from natural numbers
Each question contains Quantity I and Quantity II. Read the contents carefully and answer your questions accordingly. Quantity I: there are three numbers in the ratio 5:6:10. The sum of the largest and the smallest numbers is 126 more than the other number. Find the largest number? Quantity II: 12% of first number is equal to 25 % second number. The difference of these two numbers is 78. Then find the largest number?
Sum of 4 consecutive even number is greater than three consecutive odd numbers by 81.If the sum of the least odd and even numbers is 59 then find the sum of largest odd and even numbers
Find the largest number, which exactly divides every number of the form (n3 - n) (n - 2) where n is a natural number greater than 2.
Moyna has n chcoltes, where n is an integer such that 2050. If Moyna divides the chocolates equally among 5 children, she will have 2 chocolates remaining. If she divides the chocolates among 6 children, she will have 1 chocolate remaining. How many chocolates will remain if she divides the chocolates among 7 children?
Marium has n chocolates, where n is an integer such that 2050. If Marium divides the chocolates equally among 5 children, she will have 2 chocolates remaining. If she divides the chocolates among 6 children, she will have 1 chocolates remaining. How many chocolates will remain if she divides the chocolates among 7 children?