What is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
A
840
B
841
C
820
D
814
Correct Answer: 814
Length of the room= 15 m 17 cm
= 15 × 100 + 17
= 1517 cm.
Breadth of the room
= 9 m 2 cm
= 902 cm.
The HCF of the 1517 and 902 will be size of square tiles.HCF 1517 and 902 = 41 cm.
Area of the room
= length × breadth
= 1517 × 902 cm2
Area of tiles = 41 × 41 cm2So, number of tiles required
= $$\frac{{1517 \times 902}}{{41 \times 41}}$$
= 814 tiles