what is the area of the triangle BCD?
A
40
B
42
C
44
D
48
Correct Answer: 48
From ∆ABC, AB2 = AC2 + BC2⇒(10)2 = (6)2 + BC2⇒BC2 = (10)2 - (6)2Again from ∆DEB, DB2 = DE2 + BE2⇒(13)2 = (5)2 + BE2⇒BE2 = (13)2 - (5)2∴ BE = 12Now from ∆BCD = 12×base×height = 12×8×12 = 48