If the sides of a square is increased by 10%, by what percent will the area of the square be increased ?

If the sides of a square is increased by 10%, by what percent will the area of the square be increased ? Correct Answer 21%

ধরি,বর্গক্ষেত্রের একবাহুর দৈর্ঘ্য = x একক " ক্ষেত্রফল = <math xmlns = "http://www.w3.org/1998/Math/MathML"><msup><mi>x</mi><mn>2</mn></msup></math> বর্গএকক<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#x2234;</mo></math> 10% বৃদ্ধিতে নতুন দৈঘ্য একক = <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mi>x</mi><mo> + </mo><mi>x</mi><mo>&#xD7;</mo><mfrac><mn>10</mn><mn>100</mn></mfrac></mrow></mfenced><mo> = </mo><mfenced><mrow><mi>x</mi><mo> + </mo><mfrac><mi>x</mi><mn>10</mn></mfrac></mrow></mfenced><mo> = </mo><mfrac><mrow><mn>11</mn><mi>x</mi></mrow><mn>10</mn></mfrac></math> একক<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#x2234;</mo></math> 10% " " ক্ষেত্রফল = <math xmlns = "http://www.w3.org/1998/Math/MathML"><msup><mfenced><mfrac><mrow><mn>11</mn><mi>x</mi></mrow><mn>10</mn></mfrac></mfenced><mn>2</mn></msup></math> = <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>121</mn><msup><mi>x</mi><mn>2</mn></msup></mrow><mn>100</mn></mfrac></math> বর্গএককসুতরাং, ক্ষেত্রফল বৃদ্ধি পায় = <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mfrac><mrow><mn>121</mn><msup><mi>x</mi><mn>2</mn></msup></mrow><mn>100</mn></mfrac><mo> - </mo><msup><mi>x</mi><mn>2</mn></msup></mrow></mfenced><mo> = </mo><mfenced><mfrac><mrow><mn>121</mn><msup><mi>x</mi><mn>2</mn></msup><mo> - </mo><mn>100</mn><msup><mi>x</mi><mn>2</mn></msup></mrow><mn>100</mn></mfrac></mfenced><mo> = </mo><mfrac><mrow><mn>21</mn><msup><mi>x</mi><mn>2</mn></msup></mrow><mn>100</mn></mfrac></math> বর্গএকক<math xmlns = "http://www.w3.org/1998/Math/MathML"><mo>&#x2234;</mo></math> ক্ষেত্রফল বৃদ্ধির হার = <math xmlns = "http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mn>21</mn><msup><mi>x</mi><mn>2</mn></msup></mrow><mstyle displaystyle = "true"><mfrac><mn>100</mn><msup><mi>x</mi><mn>2</mn></msup></mfrac></mstyle></mfrac><mo>&#xD7;</mo><mn>100</mn><mo>%</mo><mo> = </mo><mfrac><mrow><mn>21</mn><msup><mi>x</mi><mn>2</mn></msup></mrow><mn>100</mn></mfrac><mo>&#xD7;</mo><mfrac><mn>1</mn><msup><mi>x</mi><mn>2</mn></msup></mfrac><mo>&#xD7;</mo><mn>100</mn><mo>%</mo></math> = 21%
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