Find the L.C.M of (1-a2),1-a, (a-1)2
A
1+a
B
1-a
C
a-1
D
(1-a)2
Correct Answer: (1-a)2
1st term = (1 - a)2 = (1 - a) (1 - a) 2nd term = 1 - a 3rd term = (a - 1)2 = { - (1 - a)}2 = (1 - a)2 = (1 - a)(1 - a) So, the L.C.M. (1 - a)2