Find the L.C.M of (1-a2),1-a, (a-1)2

Find the L.C.M of (1-a2),1-a, (a-1)2 Correct Answer (1-a)2

1st term = (1 - a)2 = (1 - a) (1 - a) 2nd term = 1 - a 3rd term = (a - 1)2 = { - (1 - a)}2 = (1 - a)2 = (1 - a)(1 - a) So, the L.C.M. (1 - a)2

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State whether the given statement is True or False. LCM (a, b, c, d) = LCM(a,(LCM(b,(LCM(c, d)))).
Find the value of (a12 + a8 + a6 - a4 + 1)/a6 where b = 3 + 2√2 and ab = 1.
a-3=0.2 হলে a12 = কত?