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How many time the following for loop will be executed ? unsigned int i for ( i=100; i > = 0, i --) printf ("%d", i)

How many time the following for loop will be executed ? unsigned int i for ( i=100; i > = 0, i --) printf ("%d", i) Correct Answer 100

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What is the output of following program? abstract class Sum { public abstract int sumOfTwo(int n1, int n2); public abstract int sumOfThree(int n1, int n2, int n3); public void disp( ){ System.out.println("Method of class Sum"); } } class DemoAbstract1 extends Sum { public int sumOfTwo(int num1, int num2) { return num1+num2; } public int sumOfThree(int num1, int num2, int num3) { return num1+num2+num3; } public static void main(String args[ ]){ Sum obj = new DemoAbstract1( ); System.out.println(obj.sumOfTwo(3, 7)); System.out.println(obj.sumOfThree(4, 3, 19)); obj.disp( ); } }
Consider the following C code. Assume that unsigned long int type length is 64 bits. unsigned long int fun (unsigned long int n) { unsigned long int i, j = 0, sum = 0 ; for (i = n; i > 1 ; i = i/2) j++ ; for ( ; j > 1 ; j = j/2) sum++ ; return (sum) ; } The value returned when we call fun with the input 240 is
What will happens if the statement free(a) is removed in the following C code?
#include#includemain(){ int *a; a=(int*)malloc(sizeof(int)); *a=100; printf("*a%d",*a); free(a); a=(int*)malloc(sizeof(int)); *a=200; printf("a%p",a); *a=200; printf("a%d",*a);}
Consider the following recursive C function that takes two arguments unsigned int rer (unsigned int n, unsigned int r) { if (n > 0) return (n%r + rer (n/r, r)); else return 0; } What is the return value of the function rer when it is called as rer (513, 2)?
Consider the following C function in which size is the number of elements in the array E: int MyX(int *E, unsigned int size) {       int Y = 0;       int Z;       int i, j, k;       for(i = 0; i < size; i++) Y = Y + E[i];       for(i = 0; i < size; i++) for(j = i; j < size; j++) {       Z = 0;       for(k = i; k <= j; k++) Z = Z + E[k];       if (Z > Y) Y = Z; }       return Y; } The value returned by the function MyX is the
Consider the following two functions. void fun1 (int n) { if (n == 0) return; printf(“%d”, n); fun2(n – 2); printf (“%d”, n); } void fun2(int n) { if (n == 0) return; printf (“%d”, n); fun1(++n); printf(“%d”, n); } The output printed when fun1 (5) is called is
Comment on the output of the following C code.
#include int main(){ int a = 1; switch (a) case 1: printf("%d", a); case 2: printf("%d", a); case 3: printf("%d", a); default: printf("%d", a);}
What is the output of this program ? #include
using namespace std;
int n(char, int);
int (*p) (char, int) = n;
int main()
{
(*p)('d', 9);
p(10, 9);
return 0;
}
int n(char c, int i)
{
cout << c << i;
return 0;
}
What will output when you compile and run the following code?#include
struct student
{ int roll;
int cgpa;
int sgpa[8]; }; void main()
{ struct student s = { 12,8,7,2,5,9 };
int *ptr;
ptr = (int *)&s;
clrscr();
printf( "%d", *(ptr+3) );
getch(); }
What will be output when you will execute following c code?#include
void main() {
signed int a = -1;
unsigned int b = -1u;
if(a == b)
printf( "The Lord of the Rings" );
else
printf( "American Beauty" );
}