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Point out the correct statement. * executes a Hive query and prints results to standard output b) executes a Hive query and prints results to standard output c) executes a Hive query and prints results to standard output d) All of the mentioned
Three concurrent processes X, Y, and Z execute three different code segments that access and update certain shared variables. Process X executes the P operation (i.e., wait) on semaphores a, b and c; process Y executes the P operation on semaphores b, c and d; process Z executes the P operation on semaphores c, d, and a before entering the respective code segments. After completing the execution of its code segment, each process invokes the V operation (i.e., signal) on its three semaphores. All semaphores are binary semaphores initialized to one. Which one of the following represents a deadlock-free order of invoking the P operations by the processes?
In Java, which exception is thrown when attempting to divide by zero?
A stone was thrown vertically upwards from the ground with a velocity of 50 m/sec. After 5 seconds another stone was thrown vertically upwards from the same place. If both the stones strike the ground at the same time, then the velocity with which the second stone was thrown should be (Assume g = 10 m/sec2)
From a building 2 balls A and B are thrown such that A is thrown upward and B is thrown downward. If vA and vB are their respective velocities on reaching the ground, then _____________
If an exception is thrown and no catch block matches the type of the thrown parameter, then _____
When a stone thrown directly upwards reaches the top, it: A. Velocity and acceleration are zero. B. The velocity is zero and the acceleration is about 10 m/s2. C. Velocity is about 10 m/s and acceleration is zero. D. The velocity is about 10 m/s and the acceleration remains the same.
What is the result of the following code snippet?

try {
int num = 10 / 0;
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}
What is the result of the following code snippet?

try {
throw new ArithmeticException();
} catch (Exception e) {
System.out.println("Exception!");
} catch (ArithmeticException e) {
System.out.println("Arithmetic Exception!");
}
What is the result of the following code snippet?

try {
throw new RuntimeException();
} catch (RuntimeException e) {
System.out.println("Runtime Exception!");
} catch (Exception e) {
System.out.println("Exception!");
}