A particle of mass m moves in a potential V(x) = $$\frac{1}{2}$$ mω2x2 + $$\frac{1}{2}$$ mμv2, where x is the position coordinate, v is the speed and ω, μ are constants. The canonical momentum of the particle is

A particle of mass m moves in a potential V(x) = $$\frac{1}{2}$$ mω2x2 + $$\frac{1}{2}$$ mμv2, where x is the position coordinate, v is the speed and ω, μ are constants. The canonical momentum of the particle is Correct Answer p = (1 - μ)mv

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