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The residue of $${\text{f}}\left( {\text{z}} \right) = \frac{{{{\text{z}}^3}}}{{{{\left( {{\text{z}} - 1} \right)}^4}\left( {{\text{z}} - 2} \right)\left( {{\text{z}} - 3} \right)}}$$      at z = 3 is

The residue of $${\text{f}}\left( {\text{z}} \right) = \frac{{{{\text{z}}^3}}}{{{{\left( {{\text{z}} - 1} \right)}^4}\left( {{\text{z}} - 2} \right)\left( {{\text{z}} - 3} \right)}}$$      at z = 3 is Correct Answer $$\frac{{27}}{{16}}$$

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