Related Questions

Capillary rise of mercury in a small diameter tube is proportional of (where, d = mercury of the rube, σ = surface tension of mercury)
A d
B 1/d
C σ
D 1/σ
Capillary rise of mercury in a small diameter tube is proportional to (where, d = diameter of the tube, σ = surface tension of mercury)
A d
B $$\frac{1}{{\text{d}}}$$
C $$\sigma $$
D $$\frac{l}{\sigma }$$
The angle of contact between a glass capillary tube of length 10 cm and a liquid is 90 degree . If the capillary tube is dipped vertically in the liquid, then the liquid:
A Will rise in the tube
B Will get depressed in the tube
C Will rise -up to 10 cm in the tube and will over flow
D Will neither rise nor fall in the tube.
The angle of contact between a glass capillary tube of length 10 cm and a liquid is 90 Degree. If the capillary tube is dipped vertically in the liquid, then the liquid:
A Will rise in the tube
B Will get depressed in the tube
C Will rise-up to 10 cm in the tube and will over flow
D Will neither rise not fall in the tube
A glass tube of smaller diameter is used while performing an experiment for the capillary rise of water because
A It is easier to see through the glass tube
B Glass tube is cheaper than a metallic tube
C It is not possible to conduct this experiment with any other tube
D All of the above
In the design of a paddle agitator, the ratio (paddle dia/tank dia) is normally taken as
A 0.1
B 0.8
C 0.25
D 0.5
The raio, (properller agitator dia/tank dia) is normally taken as
A 0.15-030
B 0.5-0.65
C 0.75-0.85
D 0.60-0.90
Working principle of mercury in glass thermometer is based on the __________ of mercury with increase in temperature.
A Increase of pressure
B Increase of thermal conductivity
C Volumetric expansion
D Differential linear expansion
Rise of liquid in a capillary tube is due to
A Cohesion
B Adhesion
C Both A & B
D Neither A nor B
Applying a pressure drop across a capillary results in a volumetric flow rate 'Q' under laminar flow conditions. The flow rate for the same pressure drop, in a capillary of the same length but half the radius is
A $$\frac{{\text{Q}}}{2}$$
B $$\frac{{\text{Q}}}{4}$$
C $$\frac{{\text{Q}}}{8}$$
D $$\frac{{\text{Q}}}{{16}}$$

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