For a mixed flow reactor operating at steady state, the rate of reaction is given by

A $$\frac{{{{\text{F}}_{{{\text{A}}_{\text{0}}}}}}}{{\text{V}}} - \frac{{{\text{d}}{{\text{C}}_{\text{A}}}}}{{{\text{dt}}}}$$
B $$\frac{{{{\text{F}}_{{{\text{A}}_{\text{0}}}}}}}{{\text{V}}} + \frac{{{\text{d}}{{\text{C}}_{\text{A}}}}}{{{\text{dt}}}}$$
C $$\frac{{{{\text{F}}_{{{\text{A}}_{\text{0}}}}}}}{{\text{V}}} \cdot {{\text{X}}_{\text{A}}}$$
D $$ - \frac{{{\text{d}}{{\text{C}}_{\text{A}}}}}{{{\text{dt}}}}$$

Correct Answer: $$\frac{{{{\text{F}}_{{{\text{A}}_{\text{0}}}}}}}{{\text{V}}} \cdot {{\text{X}}_{\text{A}}}$$

Bissoy MCQ
#Chemical Engineering #Chemical Reaction Engineering

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