In a reversible process
A
Tds = dE + dW
B
DE - dW = Tds
C
DW - dE = Tds
D
Tds - dW + dE >0
Correct Answer: Tds = dE + dW
From second law of thermodynamics :$$\eqalign{ & TdS \geqslant \delta Q \cr & \Rightarrow TdS \geqslant dU + \delta W \cr} $$
For an irreversible process $$TdS - dU - \delta W > 0$$
And for an reversible process $$TdS - dU - \delta W = 0$$
