If E is the spherical excess and R the radius of the earth, the surface area of the triangle, is
A
$$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{90}^ \circ }}}$$
B
$$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{180}^ \circ }}}$$
C
$$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{270}^ \circ }}}$$
D
$$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{360}^ \circ }}}$$
Correct Answer: $$\frac{{\pi {{\text{R}}^2}{\text{E}}}}{{{{180}^ \circ }}}$$
