Related Questions

Two forces of magnitude 3m and 2m respectively have a resultant R. if the first force is doubled, the magnitude of the resultant is doubled.Find the angle betuween forces?
A 90°
B 120°
C 135°
D 145°
3N ও 2N মানের দুইটি বলের লদ্ধি R । প্রথম বলের মান দ্বিগুণ করলে লদ্ধির মানও দ্বিগুণ হয়। বলদ্বয়ের মধ্যবর্তী কোণের মান হবে- (The resultant of two forces 3N and 2N is R. If the first force is doubled then the resultant is also doubled. The angle between the forces is-)
A 30°
B 45°
C 65°
D 120°
Parallelogram Law of Forces states, "if two forces acting simultaneously on a particle be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by
A Its longer side
B Its shorter side
C The diagonal of the parallelogram which does not pass through the point of intersection of the forces
D The diagonal of the parallelogram which passes through the point of intersection of the forces
If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is
A 30°
B 60°
C 90°
D 120°
The change in length due to a tensile or compressive force acting on a body is given by (where P = Tensile or compressive force acting on the body, $$l$$ = Original length of the body, A = Cross-sectional area of the body and E = Young's modulus for the material of the body)
A $$\frac{{{\text{P}}l{\text{A}}}}{{\text{E}}}$$
B $$\frac{{{\text{P}}l}}{{{\text{AE}}}}$$
C $$\frac{{\text{E}}}{{{\text{P}}l{\text{A}}}}$$
D $$\frac{{{\text{AE}}}}{{{\text{P}}l}}$$
The resultant of two forces P and Q is R. If Q is doubled, the new resultant is perpendicular to P. Then,
A P = R
B Q = R
C P = Q
D None of the above is correct
The resultant of the two forces ‘P’ and ‘Q’ is ‘R’. If ‘Q’ is doubled, the new resultant is perpendicular to ‘P’. Then
A P = Q
B Q = R
C Q = 2R
D None of these
The resultant of the two forces P & Q is R. If Q is doubled, the new resultant is perpendicular to P. Then
A P = Q
B Q = R
C Q = 2R
D Q = 3R
If a number of forces are acting at a point, their resultant is given by
A $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2}$$
B $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2}} $$
C $${\left( {\sum {\text{V}} } \right)^2} + {\left( {\sum {\text{H}} } \right)^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)$$
D $$\sqrt {{{\left( {\sum {\text{V}} } \right)}^2} + {{\left( {\sum {\text{H}} } \right)}^2} + 2\left( {\sum {\text{V}} } \right)\left( {\sum {\text{H}} } \right)} $$
If a number of forces are acting at a point, their resultant will be inclined at an angle $$\theta $$ with the horizontal, such that
A $$\tan \theta = \frac{{\sum {\text{H}} }}{{\sum {\text{V}} }}$$
B $$\tan \theta = \frac{{\sum {\text{V}} }}{{\sum {\text{H}} }}$$
C $$\tan \theta = \sum {{\text{V}} \times \sum {\text{H}} } $$
D $$\tan \theta = \sqrt {\sum {{\text{V}} + \sum {\text{H}} } } $$

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