The C.O.P. of a heat pump working on a reversed Carnot cycle is

$$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$

$$\frac{{{{\text{T}}_2} - {{\text{T}}_1}}}{{{{\text{T}}_1}}}$$

$$\frac{{{{\text{T}}_1} - {{\text{T}}_2}}}{{{{\text{T}}_1}}}$$

$$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$

The C.O.P. of a heat pump working on a reversed Carnot cycle is Correct Answer $$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$

The C.O.P. of a heat pump working on a reversed Carnot cycle is $$\frac{{{{\text{T}}_2}}}{{{{\text{T}}_2} - {{\text{T}}_1}}}$$

Bissoy MCQ Team

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