The resolved part of the resultant of two forces inclined at an angle 'θ' in a given direction is equal to

A The algebraic sum of the resolved parts of the forces in the given direction
B The sum of the resolved parts of the forces in the given direction
C The difference of the forces multiplied by the cosine of θ
D The sum of the forces multiplied by the sine of θ

Correct Answer: The algebraic sum of the resolved parts of the forces in the given direction

Bissoy MCQ
#Mechanical Engineering #Engineering Mechanics

Related Questions

The algebraic sum of the resolved parts of a number of forces in a given direction is equal to the resolved part of their resultant in the same direction. This is known as
A Principle of independence of forces
B Principle of resolution of forces
C Principle of transmissibility of forces
D None of these
The algebraic sum of the resolved parts of a number of forces in a given direction is equal to the resolved part of their resultant in the same direction. This is as per the principle of
A Forces
B Independence of forces
C Balance of force
D Resolution of forces
The resolved part of the resultant of two forces inclined at an angle θ in a given direction is
A Algebraic sum of the resolved parts of the forces in the direction
B Arithmetical sum of the resolved parts of the forces in the direction
C Difference of the forces multiplied by cosine θ°
D Sum of the forces multiplied by the tangent θ°
If the resultant of two equal forces has the same magnitude as either of the forces, then the angle between the two forces is
A 30°
B 60°
C 90°
D 120°
Two forces of magnitude 3m and 2m respectively have a resultant R. if the first force is doubled, the magnitude of the resultant is doubled.Find the angle betuween forces?
A 90°
B 120°
C 135°
D 145°
3N ও 2N মানের দুইটি বলের লদ্ধি R । প্রথম বলের মান দ্বিগুণ করলে লদ্ধির মানও দ্বিগুণ হয়। বলদ্বয়ের মধ্যবর্তী কোণের মান হবে- (The resultant of two forces 3N and 2N is R. If the first force is doubled then the resultant is also doubled. The angle between the forces is-)
A 30°
B 45°
C 65°
D 120°
Parallelogram Law of Forces states, "if two forces acting simultaneously on a particle be represented in magnitude and direction by two adjacent sides of a parallelogram, their resultant may be represented in magnitude and direction by
A Its longer side
B Its shorter side
C The diagonal of the parallelogram which does not pass through the point of intersection of the forces
D The diagonal of the parallelogram which passes through the point of intersection of the forces
The velocity ratio in case of an inclined plane inclined at angle 'θ' to the horizontal and weight being pulled up the inclined plane by vertical effort is
A sinθ
B cosθ
C tanθ
D cosecθ
If the resultant of two forces has the same magnitude as either of the force, then the angle between the two forces is
A 30°
B 45°
C 60°
D 120°
If a number of forces are acting at a point, their resultant will be inclined at an angle $$\theta $$ with the horizontal, such that
A $$\tan \theta = \frac{{\sum {\text{H}} }}{{\sum {\text{V}} }}$$
B $$\tan \theta = \frac{{\sum {\text{V}} }}{{\sum {\text{H}} }}$$
C $$\tan \theta = \sum {{\text{V}} \times \sum {\text{H}} } $$
D $$\tan \theta = \sqrt {\sum {{\text{V}} + \sum {\text{H}} } } $$

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