A point D is taken on the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then

A AB<sup>2</sup> + CD<sup>2</sup> = AD<sup>2</sup> + BC<sup>2</sup>
B CD<sup>2</sup> + BD<sup>2</sup> = 2AD<sup>2</sup>
C AB<sup>2</sup> + AC<sup>2</sup> = 2AD<sup>2</sup>
D AB<sup>2</sup> = AD<sup>2</sup> + BC<sup>2</sup>

Correct Answer: AB<sup>2</sup> + CD<sup>2</sup> = AD<sup>2</sup> + BC<sup>2</sup>

According to question,
Triangles mcq solution image
In ΔABC
AB2 = AC2 + BC2 . . . . . . . (i)
ΔACD
AD2 = AC2 + CD2
AC2 = AD2 - CD2 . . . . . . . (ii)
Put the value of AC2 in equation (i)
AB2 = AD2 - CD2 + BC2
AB2 + CD2 = AD2 + BC2
Bissoy MCQ
#Arithmetic Ability #Triangles

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