Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number. Correct Answer 3
$$\eqalign{ & {\text{Let}}\,{\text{the}}\,{\text{number}}\,{\text{be}}\,x \cr & {\text{Then}},\,x + 17 = \frac{{60}}{x} \cr & \Rightarrow {x^2} + 17x - 60 = 0 \cr & \Rightarrow (x + 20)(x - 3) = 0 \cr & \Rightarrow x = 3 \cr} $$