How many ounces of water must be added to a 30-ounce solution that is 40 percent alchol to dilute the solution to 25 percent alcohol?

How many ounces of water must be added to a 30-ounce solution that is 40 percent alchol to dilute the solution to 25 percent alcohol? Correct Answer 18

Let, amount of water that needs to be added i x Amount of pure alcohol before the water is added = 0.40×30 = 12 ounces Amount of pure alcohol before the water is added = 0.25 ×( 30 + x) ounces According to question, 12 = o.25 ( 30 + x) 12 - 7.5 = o.25x x = 18 ounces
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