The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is
A
1008
B
1015
C
1022
D
1032
Correct Answer: 1015
Required Number = (L.C.M of 12, 16, 18,21,28)+7
= 1008 + 7
= 1015