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A vessel is filled with liquid, 3 parts of which are water and 5 parts of syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

A vessel is filled with liquid, 3 parts of which are water and 5 parts of syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup? Correct Answer 1\/5

Suppose the vessel initially contains 8 litres of liquid.

 

Let x litres of this liquid be replaced with water.Quantity of water in new mixture =  3-3x8+xlitres.

 

Quantity of syrup in new mixture =  5-5x8 litres.

 

  3-3x8+x=5-5x8

 

=>   5x + 24 = 40 - 5x 

 

=>   10x = 16    => x = 8/5

 

So, part of the mixture replaced = 85×18 = 1/5.

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