Four dice are thrown simultaneously. Find the probability that all of them show the same face.
A
1\/216
B
1\/36
C
2\/216
D
4\/216
Correct Answer: 1\/216
The total number of elementary events associated to the random experiments of throwing four dice simultaneously is:
= 6*6*6*6=64
n(S) = 64
Let X be the event that all dice show the same face.
X = { (1,1,1,1,), (2,2,2,2), (3,3,3,3), (4,4,4,4), (5,5,5,5), (6,6,6,6)}
n(X) = 6
Hence required probability = n(X)n(S)=664 =1216
