Three unbiased coins are tossed. What is the probability of getting at most two heads?
A
3\/4
B
7\/8
C
1\/2
D
1\/4
Correct Answer: 7\/8
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) =n(E)/n(S)=7/8.