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Two fishes M and N are swimming away from a glacier in the same direction. If the height of the glacier is 800 m and the angle of elevation made by the 2 fishes are 45 and 30 degree respectively, then what is the distance between the two fishes?

Two fishes M and N are swimming away from a glacier in the same direction. If the height of the glacier is 800 m and the angle of elevation made by the 2 fishes are 45 and 30 degree respectively, then what is the distance between the two fishes? Correct Answer 800 (√3 – 1) m

Given, Angle of M fish = 45 – degree, angle of N fish = 30 – degree, height = 800m Let the distance between fish M and glacier be x m, fish N and glacier be y m. Fish M ➩ tan 45 = height / base distance ➩ 1 = 800 / x ➩ x = 800 m Fish N ➩ tan 30 = height / base distance ➩ 1 / √3 = 800 / y ➩ y = 800√3 m Distance between the two ships = y – x = 800√3 – 800 m = 800 (√3 – 1) m

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