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Which value of z would satisfy the expression log27 (3log2 (1 + log3 (1 + 2log2z)) = 1 / 3?

Which value of z would satisfy the expression log27 (3log2 (1 + log3 (1 + 2log2z)) = 1 / 3? Correct Answer 2

Given, Log27 (3log2 (1 + log3 (1 + 2log2z)) = 1 / 3 ➩ 3log2 (1 + log3 (1 + 2log2z)) = 271/3 = 3 ➩ log2 (1 + log3 (1 + 2log2z)) = 1 ➩ 1 + log3 (1 + 2log2z) = 2 ➩ log3 (1 + 2log2z) = 1 ➩ 1 + 2log2z = 3 ➩ 2log2z = 2 ➩ log2z = 1 ➩ z = 2

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