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Find the largest number which divides 397, 612 and 1300 to leave same remainder in each case.

Find the largest number which divides 397, 612 and 1300 to leave same remainder in each case. Correct Answer 43

The largest number which divides a, b and c to leave same remainder in each case = HCF (a-b, b-c, c-a). Therefore, the largest number which divides 399, 751 and 924 to leave same remainder in each case = HCF (612-397, 1300-612, 1300-397) = HCF (215, 688, 903) = 43.

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