An observer 1.5 m tall is 23.5 m away from a tower 25 m high. What is the angle of elevation of the top of the tower from the eye of the observer?

An observer 1.5 m tall is 23.5 m away from a tower 25 m high. What is the angle of elevation of the top of the tower from the eye of the observer? Correct Answer 45 degree

According to the questioBase = 23.5 m, height = 25 – 1.5 = 23.5 m Let the angle be x. ➩ Tan x = height / base ➩ Tan x = 23.5 / 23.5 ➩ Tan x = 1 ➩ x = 45 degree
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