Consider that, a ball is immersed in water at room temperature and then taken out having 18 grams of water on it, how much amount of energy is required to dry that water at room temperature?

Consider that, a ball is immersed in water at room temperature and then taken out having 18 grams of water on it, how much amount of energy is required to dry that water at room temperature? Correct Answer 41.53 KJ/mol

Heat required to eliminate water : n x ΔvapH– = (1 mol) × (44.01 kJ mol–1) = 44.01 kJ mol-1. Δvapor = ΔvapH – ΔnRT = 44.01 kJ mol-1 – 1×8.314 J/K-mol x 298 k x 10-3 = 41.53 KJ/mol. So the amount of energy needed is 41.53 KJ/mol.
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